The difference between two positive number is 72 and one of them is divided by the other, the quotient is 4.Find those numbers.
Option:
a) 22&94
b) 24&96
c) 20&92
d) 30&102
I'll be glad to check your answer.
Let the 1st # = x
And the 2nd # = y
Difference between the two # is = 72
x - y = 72 ---- Equation 1
Then, one of the # divided by the other # which = 4
x/y = 4 ----Equation 1
x - y = 72 -- eq 1
x / y = 4 -- eq 2
x = 72 + y -- eq 3
Sub eq 3 in eq 2 we get,
[(72 + y) / y] = 4
72 + y = 4y
72 = 4y - y
72 = 3y
y = 72 / 3
y = 24
Now sub y = 24 in equation 1 or equatin 3 and solve for x?
To find the two positive numbers, we can use algebraic equations to represent the given conditions. Let's assume the two numbers are x and y, where x is the larger number.
According to the first condition, the difference between the two numbers is 72:
x - y = 72 --(Equation 1)
According to the second condition, when one of the numbers is divided by the other, the quotient is 4:
x / y = 4 --(Equation 2)
Now, we have a system of two equations (Equation 1 and Equation 2) that we can solve to find the values of x and y.
To do this, we can first solve Equation 2 for x in terms of y:
x = 4y
Substituting this value of x in Equation 1, we get:
4y - y = 72
3y = 72
y = 24
Now that we have the value of y, we can substitute it back into Equation 2 to find x:
x = 4 * 24
x = 96
So, the larger number (x) is 96 and the smaller number (y) is 24.
Therefore, the correct option is b) 24&96.