find the acceleration of a 3 kg mass as it moves with a constant speed of 4 m/s along a circle of radius 2 m.
only acceleration is centripetal, toward the center = v^2/r = 16/2 = 8 m/s^2
This has nothing to do with the mass just as the previous question had nothing to do with the material being copper.
To find the acceleration of the 3 kg mass as it moves with a constant speed of 4 m/s along a circle of radius 2 m, we need to use the formula for centripetal acceleration.
Centripetal acceleration (a) is given by the equation:
a = v^2 / r
Where:
a = centripetal acceleration
v = velocity (speed)
r = radius
In this case, the mass is moving along a circle, so its velocity is tangent to the circle at any given point. This means the speed is constant, but the direction is changing. The acceleration is always directed toward the center of the circle, perpendicular to the velocity vector.
Given:
v = 4 m/s
r = 2 m
Plugging in these values into the formula, we have:
a = (4 m/s)^2 / 2 m
Simplifying:
a = 16 m^2/s^2 / 2 m
a = 8 m/s^2
Therefore, the acceleration of the 3 kg mass as it moves with a constant speed of 4 m/s along a circle of radius 2 m is 8 m/s^2.