I have tied to solve this problem but am stuck. Hoping what I have done so far is accurate but need help in conversion.
What mass, in grams, of oxygen gas (O2) is contained in a 10.5 liter tank at 27.3 degrees Celsius and 1.83 atmospheres? Show all of the work used to solve this problem.
n = PV/RT
(1.83) (10.5)
(.0821) Latm (27.3 +273 = 300.3)
molK
.779 mol
NEED TO PUT INTO GRAMS
To convert from moles to grams, you need to use the molar mass of oxygen gas (O2). The molar mass of O2 is 32 grams/mol (16 g/mol for each oxygen atom).
To find the mass of oxygen gas in grams, you can use the formula:
Mass (grams) = Number of moles × Molar mass
In this case, you have calculated the number of moles to be 0.779 mol.
Plugging in the values:
Mass (grams) = 0.779 mol × 32 g/mol
Mass (grams) = 24.928 grams
Therefore, there are approximately 24.928 grams of oxygen gas in the 10.5 liter tank at 27.3 degrees Celsius and 1.83 atmospheres.