would someone write out the whole process of the following question, including solving for y so that i can see what i am doing wrong. Thank you
Solve by the substitution method. write as an ordered pair.
8x-3y=-94
2x+22=y
8x - 3y = 94 ---- Equation 1
2x + 22 = y ---- Equation 2
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Sub y = 2x + 22 in equation 1
8x - 3(2x + 22) = 94
8x - 6x - 66 = 94
2x = 94 + 66
2x = 160
x = 160/2
x = 80
Now sub x = 8 in eq 1 or eq 2 and find for y
Sorry, I made a mistake.
Substitute x = 80 in equation 1 or equation 2 and fine for y.
Sure! To solve the system of equations using the substitution method, we need to solve one of the equations for one variable and then substitute that expression into the other equation. Let's start with the second equation, which is:
2x + 22 = y
Step 1: Solve for y in terms of x by rearranging the equation:
y = 2x + 22
Now, we can substitute this expression for y in the first equation, which is:
8x - 3y = -94
Step 2: Substitute y with 2x + 22 in the first equation:
8x - 3(2x + 22) = -94
Now, let's simplify the equation:
Step 3: Distribute the -3 to both terms inside the parentheses:
8x - 6x - 66 = -94
Step 4: Combine like terms on the left side of the equation:
2x - 66 = -94
Step 5: Add 66 to both sides of the equation to isolate the variable:
2x - 66 + 66 = -94 + 66
2x = -28
Step 6: Divide both sides of the equation by 2 to solve for x:
2x/2 = -28/2
x = -14
Now that we have the value of x, we can substitute it back into either of the original equations to solve for y. Let's use the second equation:
2x + 22 = y
Step 7: Plug in the value of x (-14) into the equation:
2(-14) + 22 = y
-28 + 22 = y
-6 = y
Therefore, the solution to the system of equations is x = -14 and y = -6.
As an ordered pair, the solution is (-14, -6).