According to the U. S. Census Bureau, the total 2008 U.S. population was 303,824,640. The chart below summarizes the 2008 population for five U.S. States.


U. S. State 2008 Population

Alaska 686,293
California 36,756,666
Hawaii 1,288,198
Idaho 1,523,816
Indiana 6,376,792


SOURCE: U. S. Census Bureau


What is the probability that a randomly selected U.S. resident did not live in Idaho? Show step by step work. Round solution to the nearest thousandth.

Would it be 1/1523816 = 0.000000656??

The probability that a randomly selected U.S. resident did live in Idaho

= 1523816/303824640

so the probability that a randomly selected U.S. resident did not live in Idaho
= 1 - 1523816/303824640

I will leave the arithmetic up to you

1523816/303824640 = 0.005

1 - 0.005 = 0.995 or would it be 0.990 when rounded to the nearest thousandth?

You would have to look at the 4th decimal which you did not show.

On my calculator, I got
.9949 , so to the nearest thousandth that would be

.995

oh okay...thank you Reiny for your help :)

To calculate the probability that a randomly selected U.S. resident did not live in Idaho, we need to consider the number of U.S. residents who did not live in Idaho and divide it by the total U.S. population in 2008.

First, we need to find the total population of all states except Idaho. We add up the populations of all the states mentioned in the chart: Alaska (686,293), California (36,756,666), Hawaii (1,288,198), and Indiana (6,376,792).

Total population of states except Idaho = 686,293 + 36,756,666 + 1,288,198 + 6,376,792 = 45,107,949

Next, we divide the total population of states except Idaho by the total U.S. population in 2008:

Probability = (Total population of states except Idaho) / (Total U.S. population in 2008) = 45,107,949 / 303,824,640

Now, we can calculate the probability using a calculator or software:

Probability ≈ 0.148394 (rounded to six decimal places)

Therefore, the probability that a randomly selected U.S. resident did not live in Idaho is approximately 0.148.