how to find the slope of the curve 17x^2+12xy=100-8y^2 at the point where y=1.
-i already d/dx but i didn't know how to find the slope of curve bcus they only give y.
d/dx=(-34x-12y)/(12x+16y)
To find the slope of the curve at a specific point, you need to evaluate the derivative with respect to x (dx/dy) at that point.
Given that you have already found the derivative to be (-34x-12y)/(12x+16y), you can proceed as follows to find the slope when y = 1:
1. Substitute y = 1 into the derivative expression:
d/dx = (-34x - 12(1)) / (12x + 16(1))
Simplify the expression:
d/dx = (-34x - 12) / (12x + 16)
2. Evaluate the expression when y = 1:
d/dx = (-34x - 12) / (12x + 16)
Substitute y = 1:
d/dx = (-34x - 12) / (12x + 16)
Now, you have the derivative expression for the slope when y = 1.