physics

A 0.10 g plastic bead is charged by the addition of 1.0 x 1010 excess electrons. What electric field (strength and direction) will cause the bead to hang suspended in the air?

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  1. The charge is Q = -10^10*e
    e is the electron charge, 1.6*10^-19 C

    You need an electric field pointed down to balance the weight of the drop. The strength of the field is given by
    E*Q = M*g

    E = M*g/Q newtons/coulomb

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    posted by drwls

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