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calc
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
Calc Please Help
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 14, 2010 
Calc. Limits
Are these correct? lim x>0 (x)/(sqrt(x^2+4)  2) I get 4/0= +/ infinity so lim x>0+ = + infinity? and lim x>0 = + infinity? lim x>1 (x^2  5x + 6)/(x^2  3x + 2) I get 2/0, so lim x> 1+ =  infinity? and lim x>1 = +
asked by Chelsea on October 13, 2010 
calculus
State which of the conditions are applicable to the graph of y = f(x). (Select all that apply.) lim x→infinity f(x) = −infinity lim x→a+ f(x) = L lim x→infinity f(x) = L f is continuous on [0, a] lim x→infinity f(x) = 0
asked by Lyric on September 22, 2011 
Math
Find the limit if it exists. lim 1/(x2) = infinity x→2+ lim 1/(x2) = negative infinity x→2 lim 1/(x2) = Does not exist x→2 lim (3x+2) = infinity x→∞ lim 999/(x^3) = 0 x→∞ Can someone check to make sure that I am
asked by David on May 19, 2016 
Calculus Limits
Question: If lim(f(x)/x)=5 as x approaches 0, then lim(x^2(f(1/x^2))) as x approaches infinity is equal to (a) 5 (b) 5 (c) infinity (d) 1/5 (e) none of these The answer key says (a) 5. So this is what I know: Since
asked by Anonymous on March 2, 2019 
calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 30, 2007 
Calculus  ratio test
infinity of the summation n=1: (e^n)/(n!) [using the ratio test] my work so far: = lim (n>infinity)  [(e^n+1)/((n+1)!)] / [(e^n)/(n!)]  = lim (n>infinity)  [(e^n+1)/((n+1)!)] * [(n!)/(e^n)]  = lim (n>infinity) 
asked by COFFEE on July 29, 2007 
math
i really don't understand why this 1lim 3/(y+4) [the lim is x>infinity] the ans is 0 while this 2lim (76x^5)/(x+3) [x>+infinity ] is  infinity. can anyone explain why the 1 is zero & the 2 is infinity.
asked by susan on July 20, 2011 
Calculus
Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x>0... Should i use the formula e= lim as x>0 (1+x)^(1/x) or e= lim as x>infinity (1+1/n)^n Am i able to substitute in x/n for x? and then say that e lim x >0
asked by Frederick E. on November 8, 2011 
Calculus
Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x>0... Should i use the formula e= lim as x>0 (1+x)^(1/x) or e= lim as x>infinity (1+1/n)^n Am i able to substitute in x/n for x? and then say that e lim x >0
asked by Frederick E. on November 9, 2011