a mixture of NaBr & NaCl has a mass of 2g & found to contain 0.75g of Na. What is the mass of NaBr in the mixture?
NaBr = molar mass NaBr
NaCl = molar mass NaCl
Na = atomic mass Na.
Let x = NaCl
y = NaBr
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x + y = 2
x(Na/NaCl) + y(Na/NaBr) = 0.75
Solve the two equations simultaneously fo x and y.
To find the mass of NaBr in the mixture, we need to determine the amount of NaCl first. Here's how you can do it:
Step 1: Determine the amount of sodium (Na) in NaBr:
Since the mass of Na is given as 0.75g, it is safe to assume that the mass of Na in NaBr is also 0.75g since NaBr contains only one sodium atom.
Step 2: Determine the amount of chlorine (Cl) in NaCl:
As NaCl contains one chlorine atom for every sodium atom, we can calculate the amount of Cl in NaCl using the following equation:
Amount of Cl = (Mass of NaCl - Mass of Na) / Molar mass of Cl
Step 3: Calculate the amount of NaBr:
Since NaBr contains one sodium atom for every bromine (Br) atom, we can use the amount of Na to determine the amount of NaBr using the following equation:
Amount of NaBr = Amount of Na / (Molar mass of Na × Ratio of NaBr to Na)
Step 4: Calculate the mass of NaBr:
To find the mass of NaBr, multiply the amount of NaBr by the molar mass of NaBr.
Please note that we need the molar masses of Na, Cl, and NaBr to calculate the required values.