you have 10 mL of a 1.0 M Ba(OH)2 solution and add it to 2.5 L of water. What is the concentration of hydroxide ionsin the diluted Ba(OH)2 solution?
[Ba(OH)2] = 1.0M x (10/2500) = ??
(Or use mL x M = mL x M)
(OH)2 = twice that.
To find the concentration of hydroxide ions in the diluted Ba(OH)2 solution, we need to consider the initial concentration of the Ba(OH)2 solution and the dilution that occurs when it is added to the water.
First, let's determine the number of moles of Ba(OH)2 in the 10 mL of 1.0 M solution:
1.0 M indicates that there is 1 mole of Ba(OH)2 per liter of solution.
Since we have 10 mL (which is 0.01 L) of the solution, the number of moles can be calculated as follows:
Moles of Ba(OH)2 = Concentration x Volume
= 1.0 M x 0.01 L
= 0.01 moles
Next, let's calculate the dilution factor when the Ba(OH)2 solution is added to 2.5 L of water:
Dilution factor = Total volume after dilution / Initial volume
= (Volume of Ba(OH)2 solution + Volume of water) / Volume of Ba(OH)2 solution
= (0.01 L + 2.5 L) / 0.01 L
= 250
Now, we can calculate the concentration of hydroxide ions in the diluted Ba(OH)2 solution:
Concentration of Ba(OH)2 solution / Dilution factor = Concentration of hydroxide ions in the diluted solution
1.0 M / 250 = 0.004 M
Therefore, the concentration of hydroxide ions in the diluted Ba(OH)2 solution is 0.004 M.