solve by factoring

2a² - 3a = -5

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2a^2-3a=-5

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2a^2-3a=-5

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2a^2-3a=-5

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2a² - 3a = -5

2a² - 3a + 5 = 0
(a + 1)(2a - 5 ) = 0

a = -1 or a = 5/2

To solve the equation 2a² - 3a = -5 by factoring, we can rearrange the equation to have a zero on one side:

2a² - 3a + 5 = 0

Now, we need to factor the quadratic expression on the left-hand side. Unfortunately, this quadratic cannot be easily factored since the discriminant (b² - 4ac) is negative. As a result, we will need to use the quadratic formula to find the solutions.

The quadratic formula states that for an equation of the form ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

In our case, a = 2, b = -3, and c = 5. Substituting these values into the quadratic formula:

a = 2
b = -3
c = 5

x = (-(-3) ± √((-3)² - 4(2)(5))) / (2(2))
= (3 ± √(9 - 40)) / 4
= (3 ± √(-31)) / 4

Since the square root of -31 is an imaginary number, we cannot simplify it further. Therefore, the solutions to the equation 2a² - 3a = -5 are:

x = (3 + √(-31)) / 4
x = (3 - √(-31)) / 4

These solutions cannot be expressed in real numbers because of the presence of the imaginary component arising from the square root of a negative number.