nitrous oxide (N2O) is used as an anesthetic. the pressure on 2.50 L of N2O changes from 105 k Pa to 40.5 kPa. If the temperature does not change, what will the new volume
6.5L
P1V1 = P2V2
To calculate the new volume of nitrous oxide (N2O) when its pressure changes from 105 kPa to 40.5 kPa, we can use the combined gas law equation:
(P1 * V1) / T1 = (P2 * V2) / T2
Given:
P1 = 105 kPa
V1 = 2.50 L
P2 = 40.5 kPa
T1 = T2 (temperature does not change)
Let's rearrange the equation to solve for V2:
V2 = (P1 * V1 * T2) / (P2 * T1)
Since T1 = T2, we can cancel out the temperature terms:
V2 = (P1 * V1) / P2
Now we can substitute the given values:
V2 = (105 kPa * 2.50 L) / 40.5 kPa
V2 ≈ 6.5196 L
Therefore, the new volume of nitrous oxide (N2O) is approximately 6.5196 L.