A major-league catcher gloves a 92 mi/h pitch and brings it to rest in 0.15 m.

1-If the force exerted by the catcher is 803 N, what is the mass of the ball?

speed = 92 mi/hr * 1 hr/3600 s * 1610 m/mi

= 41.1 m/s

average speed = 41.1/2 = 20.6 m/s

time to stop = distance/speed = .15/20.6 = .0073 second

force * time = change of momentum

803 * .0073 = m (41.1 - 0)

m = .142 kg

A catcher stops 92 mi/h pitch in his glove bring it to rest in 0.15 m. If the force exerted by the catcher is 803N, what is the mass of the ball?

To find the mass of the ball, we can use Newton's second law of motion, which states that the force applied on an object is equal to the mass of the object multiplied by its acceleration.

In this case, the pitch is brought to rest by the catcher, so the acceleration of the ball is the deceleration caused by the catcher's glove.

We can find the deceleration using the formula for acceleration:

acceleration = change in velocity / time

Given that the pitch speed is 92 mi/h and it is brought to rest, the change in velocity is 92 mi/h.

We need to convert this velocity from miles per hour to meters per second in order to use it in our calculations.

1 mile = 1.60934 kilometers
1 kilometer = 1000 meters
1 hour = 60 minutes = 3600 seconds

So, we have:

acceleration = (92 mi/h * 1.60934 km/mi * 1000 m/km) / (1 h * 3600 s/h)

Using this conversion, we find that the acceleration is approximately 41.05 m/s².

Now, we can find the mass of the ball using Newton's second law:

force = mass * acceleration

Rearranging the formula, we have:

mass = force / acceleration

Given that the force exerted by the catcher is 803 N, we can substitute the values:

mass = 803 N / 41.05 m/s²

Evaluating the expression, we find that the mass of the ball is approximately 19.53 kg.

Why did the baseball go to circus school? Because it wanted to become a juggler!

speed = 92 mi/hr * 1 hr/3600 s * 621 m/mi

= 15.9 m/s

average speed = 15.9/2 = 7.9 m/s

time to stop = distance/speed = .15/7.9 = .0189 second

force * time = change of momentum

803 * .0189 = m (15.9 - 0)

m = .955 kg