What is the concentration of NaNO2 if 2.13g of N2O3 is added to excess NaOH and the resulting solution is diluted to a total volume of 500.0 mL?
Do you want concn in units of molar? molality? normality, grams/L, or just what. The easy way to answer is g/L.
2.13 g is dissolved in 500 mL so the concn is 4.26 g/L.
or 2.13/500 = ??g/mL.
Or 2.13/molar mass = moles and
M = moles/L = ??
To determine the concentration of NaNO2 in the resulting solution, we need to follow a series of steps:
Step 1: Write the balanced chemical equation.
The given reaction involves N2O3 and NaOH, which results in the formation of NaNO2. The balanced equation is as follows:
N2O3 + 2NaOH → 2NaNO2 + H2O
Step 2: Calculate the number of moles of N2O3.
To find the number of moles, we will use the given mass and the molar mass of N2O3. The molar mass of N2O3 can be calculated by adding the atomic masses of its constituent elements - 2 nitrogen (N) atoms and 3 oxygen (O) atoms.
Molar mass of N2O3 = (2 × atomic mass of N) + (3 × atomic mass of O)
Molar mass of N2O3 ≈ (2 × 14.01 g/mol) + (3 × 16.00 g/mol) ≈ 76.02 g/mol
Now, we can calculate the number of moles of N2O3:
Number of moles of N2O3 = mass of N2O3 / molar mass of N2O3
Number of moles of N2O3 = 2.13 g / 76.02 g/mol ≈ 0.028 moles
Step 3: Convert the moles of N2O3 to moles of NaNO2.
Based on the balanced chemical equation, we can see that 1 mole of N2O3 produces 2 moles of NaNO2. Therefore, the moles of NaNO2 will be twice the moles of N2O3.
Number of moles of NaNO2 = 2 × number of moles of N2O3
Number of moles of NaNO2 = 2 × 0.028 moles = 0.056 moles
Step 4: Calculate the concentration of NaNO2.
Concentration is defined as the amount of solute divided by the volume of solution. In this case, we are given the total volume of the resulting solution.
Concentration = Number of moles of NaNO2 / Volume of solution in liters
Concentration = 0.056 moles / 0.500 L = 0.112 M
Therefore, the concentration of NaNO2 in the resulting solution is approximately 0.112 M.