Construct a truth table for the statement.

(p ↔ q) → p

To construct a truth table for the statement "(p ↔ q) → p", we need to consider all possible combinations of truth values for the variables p and q.

First, we need to determine the number of rows in the truth table. Since there are two variables (p and q), each with two possible truth values (true or false), there will be 2^2 = 4 rows in the truth table.

Next, we need to assign truth values to the variables p and q in each row. We can represent a true value as 1 and a false value as 0.

Here is the truth table for the given statement:

| p | q | p ↔ q | (p ↔ q) → p |
|---|---|-------|-------------|
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 |
| 1 | 1 | 1 | 1 |

To calculate the truth value of the statement "(p ↔ q) → p", we need to evaluate the truth value of the biconditional statement p ↔ q, and then apply the implication operator → to the result in each row.

In the first row, p is false (0), q is false (0), and the biconditional statement p ↔ q is true (1). Applying the implication operator, (1) → 0 is false (0).

In the second row, p is false (0), q is true (1), and the biconditional statement p ↔ q is false (0). Applying the implication operator, (0) → 1 is true (1).

In the third row, p is true (1), q is false (0), and the biconditional statement p ↔ q is false (0). Applying the implication operator, (0) → 1 is true (1).

In the fourth row, p is true (1), q is true (1), and the biconditional statement p ↔ q is true (1). Applying the implication operator, (1) → 1 is true (1).

Therefore, the truth table for the given statement is as shown above.