How much faster will neon effuse than krypton, given that the molar mass of krypton is 83.8 grams and that of neon is 20.18 grams?

To determine the relative rate of effusion, we can use Graham's law of effusion. Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

First, we need to calculate the square root of the molar masses of neon and krypton:
√(molar mass of neon) = √(20.18 g/mol) = 4.49 g/mol
√(molar mass of krypton) = √(83.8 g/mol) = 9.16 g/mol

Next, we can calculate the ratio of the two square roots to determine the relative rate of effusion:
Rate of effusion of neon / Rate of effusion of krypton = √(molar mass of krypton) / √(molar mass of neon)
= 9.16 g/mol / 4.49 g/mol
= 2.04

Therefore, neon will effuse approximately 2.04 times faster than krypton.

To determine how much faster neon will effuse compared to krypton, we can use Graham's law of effusion. Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

The formula for Graham's law of effusion is:

Rate(neon) / Rate(krypton) = √(Molar mass(krypton) / Molar mass(neon))

Given:
Molar mass(krypton) = 83.8 grams
Molar mass(neon) = 20.18 grams

Let's plug these values into the formula:

Rate(neon) / Rate(krypton) = √(83.8 / 20.18)

Simplifying the calculation:

Rate(neon) / Rate(krypton) = √(4.15)

Taking the square root:

Rate(neon) / Rate(krypton) ≈ 2.03

From the equation, we can see that neon will effuse approximately 2.03 times faster than krypton.