How many moles of nitrogen N are there in 71.0g of Nitrous Oxide(N2O)?

moles = grams/molar mass

To determine the number of moles of nitrogen (N) in 71.0g of Nitrous Oxide (N2O), we need to use the molar mass of N2O and calculate the number of moles using the formula:

Number of moles = mass (in grams) / molar mass

The molar mass of N2O can be calculated by adding the atomic masses of its atoms (nitrogen and oxygen):

Molar mass of N2O = (atomic mass of N) × 2 + atomic mass of O

The atomic masses of nitrogen (N) and oxygen (O) can be found on the periodic table:

Atomic mass of N = 14.01 g/mol
Atomic mass of O = 16.00 g/mol

Substituting these values:

Molar mass of N2O = (14.01 g/mol) × 2 + 16.00 g/mol
= 28.02 g/mol + 16.00 g/mol
= 44.02 g/mol

Now, we can calculate the number of moles of N with the given mass:

Number of moles = 71.0g / 44.02 g/mol

Calculating this:

Number of moles = 1.612 mol (rounded to three decimal places)

Therefore, there are approximately 1.612 moles of nitrogen (N) in 71.0g of Nitrous Oxide (N2O).

To calculate the number of moles of nitrogen (N) in a given amount of Nitrous Oxide (N2O), we need to follow these steps:

1. Determine the molar mass of N2O:
The molar mass of N2O can be calculated by summing up the atomic masses of nitrogen (N) and oxygen (O) in the compound. Given that the atomic masses are approximately 14.01 g/mol for N and 16.00 g/mol for O, we can calculate the molar mass of N2O:

Molar mass of N2O = (2 * molar mass of N) + molar mass of O
= (2 * 14.01 g/mol) + 16.00 g/mol
= 28.02 g/mol + 16.00 g/mol
= 44.02 g/mol

2. Calculate the number of moles of N2O:
Moles = Mass / Molar mass
The given mass of N2O is 71.0 g. Plugging these values into the formula, we can find the number of moles:

Moles of N2O = 71.0 g / 44.02 g/mol
= 1.611 mol (rounded to three decimal places)

3. Determine the number of moles of N:
Since there are two moles of N in one mole of N2O, we multiply the number of moles of N2O by 2 to find the number of moles of N:

Moles of N = 2 * Moles of N2O
= 2 * 1.611 mol
= 3.222 mol (rounded to three decimal places)

Therefore, there are approximately 3.222 moles of nitrogen (N) in 71.0g of Nitrous Oxide (N2O).

3.56 mole