how many grams of Nh3 are produced from 5028g CaCn2?
See your post below.
Note also that CaCn2 means nothing but you wrote it in both posts.
To determine the number of grams of NH3 produced from 5028g of CaCn2, we need to first balance the chemical equation for the reaction and then use stoichiometry to calculate the amount of NH3 produced.
The balanced chemical equation for the reaction between CaCn2 and water to produce NH3 is:
CaCn2 + 3H2O -> 2NH3 + CaCO3
From the balanced equation, we can see that for every 1 mole of CaCn2 reacted, 2 moles of NH3 are produced.
1. Calculate the number of moles of CaCn2:
Moles of CaCn2 = Given mass of CaCn2 / Molar mass of CaCn2
The molar mass of CaCn2 (Calcium Cyanamide) is calculated by finding the molar mass of each element in the compound:
Molar mass of CaCn2 = (Molar mass of Ca) + 2(Molar mass of C) + (Molar mass of N)
You can find the molar masses of the elements from the periodic table.
2. Convert moles of CaCn2 to moles of NH3 using the stoichiometric ratio:
Moles of NH3 = Moles of CaCn2 × (2 moles NH3 / 1 mole CaCn2)
3. Calculate the mass of NH3:
Mass of NH3 = Moles of NH3 × Molar mass of NH3
The molar mass of NH3 (Ammonia) is calculated by finding the molar mass of each element in the compound:
Molar mass of NH3 = (Molar mass of N) + 3(Molar mass of H)
4. Substitute the values into the equations and calculate the mass of NH3.
The final calculation will give you the answer in grams of NH3 produced from 5028g of CaCn2.