# Calc 3

intersect x^2+y^2=36-8x^2-8y^2

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asked by Katie
1. with .... ?

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posted by Reiny
2. x^2+y^2=36-8x^2-8y^2

x^2+8x^2+y^2+8y^2=36

9x^2+9y^2=36 Divide both sides with 9

x^2+y^2=4

That is circle.

x^2+y^2=R^2

Coordinates of center: 0,0

Radius: R=2

Intersect:

For x=0 y^2=4, y=sqrt(4)= +or- 2

For y=0 x^2=4, x=sqrt(4)= +or- 2

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