Calc 3

intersect x^2+y^2=36-8x^2-8y^2

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asked by Katie
  1. with .... ?

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    posted by Reiny
  2. x^2+y^2=36-8x^2-8y^2

    x^2+8x^2+y^2+8y^2=36

    9x^2+9y^2=36 Divide both sides with 9

    x^2+y^2=4


    That is circle.

    x^2+y^2=R^2

    Coordinates of center: 0,0

    Radius: R=2

    Intersect:

    For x=0 y^2=4, y=sqrt(4)= +or- 2


    For y=0 x^2=4, x=sqrt(4)= +or- 2

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