Verify that each trigonometric equation is an identity tan^2+1/sec α =sec α

I will assume you meant

(tan^2 Ø + 1)/sec Ø = sec Ø

by the Pythagorean identity
tan^2Ø + 1 = sec^2 Ø , so ....

LS = sec^2 Ø/secØ
= secØ
= RS