Question:
A sample of Freon-12 (CF2Cl2) occupies 2.261 x 101 L at 337 K and 2.917 x 102 kPa. Find its volume (in L) at standard temperature and pressure (STP).
Equation:
p1v1/t1=p2v2/t2
My Work:
(2.917 x 102 kPa)(2.261x101 L)/337K = (101.3 kpa)( x )/273 k
My Answer:
543.4 L
Is this the correct way to do this? In what form should the answer be put?
Oops, the 101 is 10^1, Sorry.
I realize my mistake now.
Yes, your approach and equation are correct. However, there is a slight mistake in your calculation. Let's go through it step by step to find the correct volume at standard temperature and pressure (STP).
Given:
p1 = 2.917 x 10^2 kPa (initial pressure)
v1 = 2.261 x 10^1 L (initial volume)
t1 = 337 K (initial temperature)
p2 = 101.3 kPa (final pressure at STP)
t2 = 273 K (final temperature at STP)
Using the equation:
p1v1/t1 = p2v2/t2
We can rearrange it to solve for v2:
v2 = (p1v1t2) / (p2t1)
Now, let's substitute the values:
v2 = (2.917 x 10^2 kPa) * (2.261 x 10^1 L) * (273 K) / (101.3 kPa) * (337 K)
Calculating this expression, we get:
v2 ≈ 69.33 L
So, the correct volume at STP is approximately 69.33 L.
The answer should be rounded to the appropriate number of significant figures, which, in this case, is three significant figures since the given values have three significant figures. Therefore, the final answer should be written as 69.3 L.