find the value of C such that the graph of 3x+C=5y has an X- intercept of (-4,0).
when y = 0, x = -4
3(-4) + C = 0
C = 12
If x = -4, then y = 0.
3(-4) + C = 5(0)
Solve.
To find the value of C, we need to substitute the coordinates of the X-intercept (-4, 0) into the equation 3x + C = 5y and solve for C.
Step 1: Substitute the X-intercept coordinates into the equation:
3(-4) + C = 5(0)
Simplifying the equation gives:
-12 + C = 0
Step 2: Solve for C by isolating it on one side of the equation:
C = 12
Therefore, the value of C is 12.
To find the value of C such that the graph of the equation 3x + C = 5y has an x-intercept of (-4,0), we need to substitute the values of the x-intercept into the equation and solve for C.
Given x-intercept: (-4, 0)
First, let's substitute the values of the x-intercept into the equation:
3(-4) + C = 5(0)
Simplifying, we have:
-12 + C = 0
To solve for C, we will isolate it on one side of the equation. Let's add 12 to both sides:
-12 + 12 + C = 0 + 12
Simplifying further:
C = 12
Therefore, the value of C that makes the graph of the equation 3x + C = 5y have an x-intercept of (-4,0) is C = 12.