find the value of C such that the graph of 3x+C=5y has an X- intercept of (-4,0).

when y = 0, x = -4

3(-4) + C = 0
C = 12

If x = -4, then y = 0.

3(-4) + C = 5(0)

Solve.

To find the value of C, we need to substitute the coordinates of the X-intercept (-4, 0) into the equation 3x + C = 5y and solve for C.

Step 1: Substitute the X-intercept coordinates into the equation:
3(-4) + C = 5(0)

Simplifying the equation gives:
-12 + C = 0

Step 2: Solve for C by isolating it on one side of the equation:
C = 12

Therefore, the value of C is 12.

To find the value of C such that the graph of the equation 3x + C = 5y has an x-intercept of (-4,0), we need to substitute the values of the x-intercept into the equation and solve for C.

Given x-intercept: (-4, 0)

First, let's substitute the values of the x-intercept into the equation:
3(-4) + C = 5(0)

Simplifying, we have:
-12 + C = 0

To solve for C, we will isolate it on one side of the equation. Let's add 12 to both sides:
-12 + 12 + C = 0 + 12

Simplifying further:
C = 12

Therefore, the value of C that makes the graph of the equation 3x + C = 5y have an x-intercept of (-4,0) is C = 12.