A solution of H2SO4 with a modal concentration 6.25m has a density of 1.300 g/ml. What is the molar concentration?
Do you mean molal concn of 6.25m?
6.25 m means 6 .25 moles/1000g solvent.
grams solute = 6.25*40 = 250 grams.
Total mass of solute + solvent = 1000 + 250 = 1250 grams soln.
volume = mass/density = 1250g/1.30 = ??
M = moles/L soln.
The boiling point of an aq solution 102.11 C. What is the freezing point?
To determine the molar concentration of a solution, we need to use the relationship between the solution's molarity (M), its density (d), and the molar mass of the solute. In this case, the solute is sulfuric acid (H2SO4).
We are given that the density of the solution is 1.300 g/ml. This means that for every 1 ml of the solution, it has a mass of 1.300 grams.
We also know the modal concentration of the sulfuric acid solution is 6.25 M.
To find the molar concentration (M), we can use the following formula:
M = (concentration in g/L) / (molar mass in g/mol)
First, let's calculate the concentration in g/L. We know that the density is 1.300 g/ml, so we can convert it to g/L by multiplying it by 1000:
(1.300 g/ml) * (1000 ml/L) = 1300 g/L
Next, we need to find the molar mass of sulfuric acid (H2SO4). The molar mass of hydrogen (H) is approximately 1 g/mol, and the molar mass of sulfur (S) is approximately 32 g/mol. The molar mass of oxygen (O) is approximately 16 g/mol. Adding these up:
(2 * 1 g/mol for hydrogen) + (1 * 32 g/mol for sulfur) + (4 * 16 g/mol for oxygen) = 98 g/mol
Now, we can substitute the values into the formula:
M = (1300 g/L) / (98 g/mol)
M ≈ 13.27 M
Therefore, the molar concentration of the H2SO4 solution is approximately 13.27 M.