Iron forms two chlorides.One gram of the first chloride produces 2.26g of silver chloride and one gram of the second chloride produces 2.65g of silver chloride.Prove that these data illustrate the law of multiple proportions
Please provide detailed answer
To prove that these data illustrate the law of multiple proportions, we need to analyze the ratio of the masses of the two chlorides and the masses of the silver chloride produced.
Let's call the first chloride "Chloride 1" and the second chloride "Chloride 2".
According to the given information, when 1g of Chloride 1 reacts with silver, it produces 2.26g of silver chloride. Similarly, when 1g of Chloride 2 reacts with silver, it produces 2.65g of silver chloride.
Now, we need to find the ratio of the masses of the two chlorides and the ratio of the masses of silver chloride produced.
The ratio of the masses of the two chlorides can be calculated using the given information:
Mass of Chloride 1 / Mass of Chloride 2 = 1g / 1g = 1/1
This tells us that the two chlorides have an equal mass of 1g.
Next, we calculate the ratio of the masses of silver chloride produced:
Mass of Silver Chloride from Chloride 1 / Mass of Silver Chloride from Chloride 2 = 2.26g / 2.65g = 0.853
This ratio is not equal to 1, indicating that the ratio of the masses of silver chloride produced is different for the two chlorides.
According to the law of multiple proportions, when two elements (in this case, iron and chlorine) combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element are in ratios of small whole numbers.
In this case, we see that the ratio of the masses of silver chloride produced is not 1, but rather 0.853. Therefore, the law of multiple proportions is NOT illustrated in this data.
well, if it is the law of multiple proportions, the increase chlorine in one of the chlorides is a whole number ratio.
You know AgCl is the formula for silver chloride, and chlorine represents a percent of the mass (35.4/(35.2+107.8)=24.7 percent
so the chlorine in each sample is
a) 2.26*.247=.558 grams Cl
b) 2.65*.247=.655 grams Cl
Now each of the chlorides had a total mass of 1 gram, so the iron in each one
was (1-.558)=.442grams
and (1-.655)=.345 grams.
now we look at mole ratios
first chloride
moles iron: .442/55.8
moles chloride=.558/35.4
ratio of chloride to iron moles:
ratio moles firstsample: .558*55.8/.442*35.4=2
second chloride:
moles iron=
ratio moles second sample:
.655*55.8/.345*35.4=3
That sure looks like whole number ratios to me.