# trigonometry

a man measured the angle of elevation of the top of a tower to be 70 degree. When he walked 300 m. further, the angle of elevation of the top was 35 degree. What is the height of the tower?

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1. make a diagram

label the tower AB , where A is the top of the tower.
label the man's first position C, his second position D
so that DC = 300
angle D = 35°
angle ACD = 110° , so then
angle DAC = 35°

so the triangle is isosceles (lucky) and AC = 300
Then in the right-angled triangle ACB ,
sin70 = AB/300
AB = 300sin70 = 281.9 m

(had the triangle not been isosceles, I would have used the Sine Law to find AC )

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posted by Reiny
2. A BOY OBSERVED THAT THE ANGLE OF ELEVATION OF THE TOP OF A TOWER IS 32 Degree HE THEN WALKS 8m Towards The Tower And THEN DISCOVER THAT THE OF Angle Of Elevation Is 43degree .Find The Height Of The Tower

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