What mass of crystals will form when a hot saturated copper sulphate solution made by dissolving 60 g of copper sulphate crystals in 100 cm3 of water at 60 degree Celsius is cooled to 25 degree Celsius?

Have you looked at the solubility differences at 60 and 30C?

To calculate the mass of crystals that will form when the solution is cooled, we need to understand the concept of solubility.

Solubility is the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature. In this case, the solute is copper sulphate (CuSO4) and the solvent is water.

First, we need to determine if the given solution is saturated or not. A saturated solution is one that contains the maximum amount of solute that can dissolve at a specific temperature.

The solubility of copper sulphate in water increases with temperature. According to the information provided, we have a hot saturated solution at 60 degrees Celsius.

To find the maximum amount of copper sulphate that can dissolve, we need to know the solubility of copper sulphate in water at this temperature. Let's assume that the solubility of copper sulphate at 60 degrees Celsius is 100 g/100 cm3 (just as an example).

Since we have initially dissolved 60 g of copper sulphate in 100 cm3 of water, and the solution is saturated, it means that 100 cm3 of water can hold a maximum of 100 g of copper sulphate at 60 degrees Celsius.

Now, we want to determine how much copper sulphate will crystallize out when the solution is cooled to 25 degrees Celsius.

To do this, we need to calculate the difference between the amount that can dissolve at 25 degrees Celsius (let's say it's 50 g/100 cm3) and the amount that was initially dissolved (60 g).

At 25 degrees Celsius, 100 cm3 of water can hold a maximum of 50 g of copper sulphate. This means that 10 g of copper sulphate will crystallize out when the solution is cooled.

Therefore, the mass of crystals that will form when the solution is cooled to 25 degrees Celsius is 10 grams.