physics

A ball is dropped from top of a building.if the distance travelled by ball in the last third of total time is 10m,the height of building is

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asked by Nitin
  1. let t be the time of fall.

    then
    10=1/2 g (1/3t)^2+vi*2/3 t

    but vi at the end of two thirds is
    vi=g (2/3 t) so..

    10=1/2 g (t/3)^2 + g (2/3t)^2
    solve for time of fall, t
    then, h=1/2 g t^2

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