If a deaf person HAS A DB loss of 76.1 for their right ear and a DB loss of 82.2 for their left ear than what is the persons DB loss?
I don't understand how I would find the persons DB loss.
Check this site.
http://www.earinfo.com/how-to-read
To find the person's total dB loss, you need to consider the individual dB losses in each ear. dB loss is measured on a logarithmic scale, which means that you cannot simply add the two values together. Instead, you need to use a formula to calculate the total dB loss.
The formula to calculate the total dB loss for two ears is as follows:
Total dB loss = 10 * log10(10^(dB loss of ear1/10) + 10^(dB loss of ear2/10))
Using this formula, let's calculate the person's total dB loss:
Total dB loss = 10 * log10(10^(76.1/10) + 10^(82.2/10))
First, convert the dB losses to the linear scale by dividing each value by 10:
Total dB loss = 10 * log10(10^(7.61) + 10^(8.22))
Next, calculate the power of each of these exponential values:
Total dB loss = 10 * log10(1941.95 + 6013.45)
Add the two values together:
Total dB loss = 10 * log10(7955.4)
Calculate the logarithm of the sum:
Total dB loss = 10 * 3.90037
Finally, multiply by 10:
Total dB loss ā 39.004 dB
Therefore, the person's total dB loss is approximately 39.004 dB.