Bobpursley for this question please, physics

I don't understand though why you can make w/mlambda I thought it was the otherway around? (in regards to this

w/N sinTheta= m lambda

N= w/(m lambda) * sinTheta

N= w/(m lambda) * x/L

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asked by URGENT
  1. I think I figured it out, you just switch the N and the mlambda, correct?

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    posted by URGENT

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