Math

How many positive 3-digit integers contain only odd digits?

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asked by Daniel
  1. first digit has to be 1,3,5,7,9
    as does second, and third.

    number odd numbers= 5*5*5=125
    and curiously, the number of even digits must be 4*5*5 (lead digit cannot be zero)=100
    Now, containing one odd digit.
    4*5*5+5*5*5+4*5*5=325 in two instances, first digit is only of four choices..
    containg two odd digits
    2*5*5*5 + 4*5*5 (second term is first digit is even)= 250+100

    all of those should add to 9*10*10=900
    checking: 350+325+100+125=900

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