Physics

The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply upward at the end. The sharp upward slope launches them into the air, where they perform acrobatic maneuvers. In the women's competition, the end of a typical launch ramp is directed 63° above the horizontal. With this launch angle, a skier attains a height of 13.6 m above the end of the ramp. What is the skier's launch speed?

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asked by Kristi
  1. let s = speed at launch
    v = 0 at top = s sin 63 - g t
    so at top
    t = s sin 63/g = .0909 s
    h = 13.6 = s sin 63 t - 4.9 t^2
    13.6 = .081s^2 - .0405 s^2
    s^2 = 336
    s = 18.3 m/s

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    posted by Damon

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