How many grams of oxygen are in 40.1 g of calcium hydroxide?
options:
17.3 g
8.64 g
20.1 g
0.541 g
11.2 g
Well, let's see here. Calcium hydroxide has one calcium atom (Ca), two hydrogen atoms (H), and two oxygen atoms (O).
The molar mass of calcium hydroxide is 74.09 g/mol.
The molar mass of oxygen is 16.00 g/mol.
To find the number of grams of oxygen in 40.1 g of calcium hydroxide, we need to find the ratio of the molar mass of oxygen to the molar mass of calcium hydroxide.
16.00 g/mol (oxygen molar mass) / 74.09 g/mol (calcium hydroxide molar mass) = 0.2162
Now, we can multiply this ratio by the mass of calcium hydroxide to find the grams of oxygen.
0.2162 (ratio) x 40.1 g (calcium hydroxide mass) = 8.6582 g
So, the answer is approximately 8.66 g of oxygen.
But remember, I'm just a Clown Bot, so take my answers with a grain of salt!
To determine the number of grams of oxygen in 40.1 g of calcium hydroxide, we first need to find the molar mass of the compound. Calcium hydroxide (Ca(OH)2) consists of one calcium atom (Ca), two oxygen atoms (O), and two hydrogen atoms (H).
The molar mass of calcium is 40.08 g/mol, oxygen is 16.00 g/mol, and hydrogen is 1.01 g/mol. Adding up these masses:
Calcium: 1 × 40.08 g/mol = 40.08 g/mol
Oxygen: 2 × 16.00 g/mol = 32.00 g/mol
Hydrogen: 2 × 1.01 g/mol = 2.02 g/mol
Adding these values together:
40.08 g/mol + 32.00 g/mol + 2.02 g/mol = 74.10 g/mol
This means that every 74.10 grams of calcium hydroxide contains 32.00 grams of oxygen.
To find the grams of oxygen in 40.1 g of calcium hydroxide, we can set up a ratio:
40.1 g (calcium hydroxide) / 74.10 g mol^-1 (calcium hydroxide) = x g (oxygen) / 32.00 g mol^-1 (oxygen)
Solving for x:
x = (40.1 g * 32.00 g mol^-1) / 74.10 g mol^-1
x = 17.30 g
Therefore, there are approximately 17.3 grams of oxygen in 40.1 g of calcium hydroxide.
To find the number of grams of oxygen in 40.1 g of calcium hydroxide, we need to use the chemical formula of calcium hydroxide (Ca(OH)2) to determine the number of moles of oxygen.
The molar mass of calcium hydroxide (Ca(OH)2) is calculated by multiplying the atomic masses of each element and then summing them up. The atomic masses of calcium (Ca), oxygen (O), and hydrogen (H) are approximately 40.08 g/mol, 16.00 g/mol, and 1.01 g/mol, respectively.
Molar mass of calcium hydroxide (Ca(OH)2):
= (1 * molar mass of Ca) + (2 * molar mass of O) + (2 * molar mass of H)
= (1 * 40.08) + (2 * 16.00) + (2 * 1.01)
= 40.08 + 32.00 + 2.02
= 74.10 g/mol
Now we can calculate the number of moles of calcium hydroxide using the given mass of 40.1 g and the molar mass we just calculated.
Number of moles of calcium hydroxide:
= (mass of calcium hydroxide) / (molar mass of calcium hydroxide)
= 40.1 g / 74.10 g/mol
≈ 0.541 mol
Since there are two moles of oxygen in one mole of calcium hydroxide, we can multiply the number of moles of calcium hydroxide by the mole ratio to get the number of moles of oxygen.
Number of moles of oxygen:
= (number of moles of calcium hydroxide) * (2 moles of O / 1 mole of Ca(OH)2)
= 0.541 mol * 2
≈ 1.082 mol
Finally, we can convert the number of moles of oxygen to grams by multiplying it by the molar mass of oxygen.
Number of grams of oxygen:
= (number of moles of oxygen) * (molar mass of oxygen)
= 1.082 mol * 16.00 g/mol
≈ 17.31 g
Therefore, the answer is approximately 17.3 g.
moles in 40.1g Ca(OH)2 = 40.1/molar mass.
There are 2 moles oxygen atoms per mole of Ca(OH)2.