How many milliliters of 0.355 M NaF solution are needed to react completely with 24.6 mL of 0.216 M CaCl2 solution? How many grams of CaF2 will be formed? The reaction is
CaCl2(aq) + 2NaF(aq) → CaF2(s) + 2NaCl(aq)
According to your balanced equation, each mole of CaCl2 needs one mole of NaF.
Moles of CaCl2: .0246*.216
volume of NaF=that/.355 in liters.
To find the volume of NaF solution needed to react completely with CaCl2 solution, we need to use the concept of stoichiometry.
Step 1: Write the balanced chemical equation:
CaCl2(aq) + 2NaF(aq) → CaF2(s) + 2NaCl(aq)
Step 2: Determine the ratio between the coefficients:
From the balanced equation, we can see that 1 mole of CaCl2 reacts with 2 moles of NaF.
Step 3: Convert the given volume of CaCl2 solution to moles:
Use the given concentration and volume to calculate the moles of CaCl2:
Moles of CaCl2 = concentration (M) x volume (L)
Given: Concentration of CaCl2 = 0.216 M and Volume of CaCl2 = 24.6 mL
Convert mL to L:
Volume (L) = 24.6 mL / 1000 = 0.0246 L
Moles of CaCl2 = 0.216 M x 0.0246 L = 0.00530 moles
Step 4: Use the stoichiometry to find the moles of NaF required:
From the balanced equation, we know that 1 mole of CaCl2 reacts with 2 moles of NaF.
Moles of NaF = 2 x Moles of CaCl2 = 2 x 0.00530 = 0.0106 moles
Step 5: Convert the moles of NaF to the volume needed:
Use the given concentration of NaF to find the volume:
Volume (L) = Moles of NaF / Concentration (M) = 0.0106 moles / 0.355 M = 0.0299 L
Convert L to mL:
Volume (mL) = 0.0299 L x 1000 = 29.9 mL
Therefore, we need approximately 29.9 mL of the 0.355 M NaF solution to react completely with the 24.6 mL of 0.216 M CaCl2 solution.
Now, let's calculate the grams of CaF2 formed:
Step 1: Use the moles of CaCl2 calculated earlier (0.00530 moles) and the molar ratio from the balanced equation to find the moles of CaF2:
From the balanced equation, we know that 1 mole of CaCl2 reacts with 1 mole of CaF2.
Moles of CaF2 = 0.00530 moles
Step 2: Convert moles of CaF2 to grams using the molar mass of CaF2:
The molar mass of CaF2 is 78.08 g/mol.
Grams of CaF2 = Moles of CaF2 x Molar mass of CaF2 = 0.00530 moles x 78.08 g/mol = 0.414 g
Therefore, approximately 0.414 grams of CaF2 will be formed.