solve the following using substitution

8x-4y=16
y=2x-4

8x-4(2x-4)=16
8x-8x+16=16
0x+16=16
so what do i do now?

Those two equations are the same.

Look at your first equation dividing both sides by 4
2 x - y = 4 or y = 2x-4 which is the second equation exactly. There is no intersection of a line with itself in a point. The system of two equations given has no solution.

Thank you that is what I thought but wasn't sure when I did not come up with an answer.

uyg

Now that you have simplified the equation, "0x + 16 = 16," which indicates that any value of x will satisfy the equation, you have found that the equation is consistent and dependent. This means that there are infinitely many solutions to the system of equations.

To find the solutions, you can choose any value for x and substitute it back into either of the original equations to solve for y.

For example, let's choose x = 0:

Using the second equation, y = 2(0) - 4
Simplifying further, y = -4

So, when x = 0, y = -4 is a solution to the system of equations.

You can repeat this process with any other value of x to find more solutions.