# trig

find cos (x/2) when sint =12/13

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asked by Raquel
1. sint = 12/13
then cost = 5/13 , by Pythagoras.

you probably meant find cos (t/2)

using cos 2A = 2cos^2 A - 1
cost = 2cos^2 (t/2) - 1
18/13 = 2cos^2 (t/2)
9/13 = cos^2 (t/2)
cos (t/2) = 3/sqrt(13)

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posted by Reiny

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