If a = 6 cm, b = 6 cm, and C = 46°, what is the approximate area of ABC?
find side c with the law of cosines:
c^2=a^2+b^2-2abCosC
then, as you know c, find area with Heron's formula.
http://mste.illinois.edu/dildine/heron/triarea.html
c^2=a^2+b^2-2abCosC
then, as you know c, find area with Heron's formula.
http://mste.illinois.edu/dildine/heron/triarea.html