Given the following sets, select the statement below that is true.
A = {l, a, t, e, r}, B = {l, a, t, e},
C = {t, a, l, e}, D = {e, a, t}
Sorry about that....
Given the following sets, select the statement below that is true.
A = {l, a, t, e, r}, B = {l, a, t, e}, C = {t, a, l, e}, D = {e, a, t}
B ⊂ C and C ⊆ A
C ⊆ B and D ⊂ B
D ⊂ A and A ⊂ D
B ⊂ A and C ⊂ D
D ⊆ A and A ⊂ C
⊂ means "a proper subset of"
P ⊂ Q requires that every element of P is also in element Q, and in addition, P cannot be equal to Q.
⊆ means "a subset of, or equal to"
Based on the given information, give an attempt at the solution.
my answer would be C ⊆ B and D ⊂ B...is that correct?
Your answer is correct.
C={t,a,l,e}
B={l,a,t,e}
Since they contain exactly the same elements, we cannot say C⊂B, nor B⊂C, but C⊆B or B⊆C would both be correct.
Also, since
D = {e, a, t}
every element of D is in C, while the element "l" that is in C but not n D.
We can therefore safely say that D is a proper subset of C.
To determine which statement is true, we need to compare the given sets.
1. A ⊆ B: This statement is false because B is a subset of A, not the other way around.
2. A = C: This statement is false because C does not contain the letter 'r', which is in set A.
3. B ⊆ C: This statement is true because B is a subset of C. Every element in set B (l, a, t, e) is also present in set C.
4. C ⊂ D: This statement is true because C is a proper subset of D. Every element in set C (t, a, l, e) is also present in set D, and D contains an additional element 'r' that is not in C.
So, the correct statement is "B ⊆ C".