physics

A 1000 Kgs Vehicle moving with a sppeed of 20 meter per sec. is brought to rest in a distance of 50 metres. find the acceleration

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asked by Anjani
  1. Vf^2 = Vo^2 = + 2ad,
    a = (Vf^2-Vo^2) / 2d,
    a = (0-(20)^2) / 100 = -4m/s^2.

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    posted by Henry

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