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a stock clerk had 600 pads on hand. He then issued 3/8 of his supply of pads to division X,1/4 to division Y and 1/6 to division Z. The number of pads remaining in stock is? I don't get how to solve this problem. In arithmetic
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Find two numbers such that the sum of the first plus three times the second is 600 and their product is a maximum. x + 3y=600 xy is a max. This is the problem statement. let U be the function equal to xy. U=xy = y(6003y) Now,
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asked by pat on January 19, 2011 
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i really don't get this one. A stock clerk had 600 pads on hand. He then issued 3/8 of his supply of pads to division x, 1/4 to division y and 1/6 to division z. The number of pads remaning in stock is? 125 why and how? 3/8 x 600
asked by chris on July 25, 2007 
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find the general term that describes the following sequens 600,300,150,75 I the thing is that you divide each of them by 2 so I would go y(n)= 600/ 2^n but how do I check if this is right? is this right? It is right. That would
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