what is the equation of the line whose slope is -3 and which passes through (0,5)?
To find the equation of a line given its slope and a point it passes through, you can use the point-slope form of a linear equation.
The point-slope form is given by:
(y - y1) = m(x - x1)
where (x1, y1) represents the given point, and m represents the slope.
In this case, the slope (m) is -3, and the given point is (0, 5). Plugging in these values into the point-slope form, we get:
(y - 5) = -3(x - 0)
Simplifying the equation further, we have:
y - 5 = -3x
Finally, we can write the equation in the slope-intercept form, which is in the form y = mx + b, where b represents the y-intercept:
y = -3x + 5
So, the equation of the line with a slope of -3 and passing through the point (0, 5) is y = -3x + 5.
WHAT IS THE EQUATION OF THE LINE THAT PASSES THROUGH THE POINTS (2,5) AND (3,10)
bob
Try using the slope formula (y2-y1)/(x2-x1)
y=mx +b
5 = (-3) 0 + b
so b = 5
y = -3 x + 5