126a(-1/9a)(1/7a cubed) and the answer to this in my book says -2a to the fith. How does it work, i've tried multiple times.
Is it 1/(7a)3 OR
1/7(a)3
(1/7a then the three)
For 126*(-1/9a)*(1/7a)3, I don't get anything like -2a5.
but it's 126a(-1/9a)(1/7a3)
Let me write it different it's
126a times negative one ninth "a" times one seventh "a cubed"
and the answer says negative 2a to the fifth
Must be
126 a (-1/9)a (1/7) a^3
That gives you the answer you are looking for.
126 a (-1/9)a (1/7) a^3
is
[ -126/ (9*7) ] (a*a*a^3)
-2 a^5
You REALLY need to learn to use parentheses for these problems because what you have written here is not what you started with. I will write what I now think the problem is.
126a(-1/9)a*(1/7)*a3
= -1*(126/9*7) = 2
a*a*a3 = a5
So the book is correct. The answer is -2a5
To understand how to simplify the expression 126a(-1/9a)(1/7a^3) and arrive at -2a^5, let's break it down step by step:
Step 1: Distribute the numbers
Start by distributing the numerical coefficient (126) to the numbers inside the parentheses:
126 * (-1/9) * (1/7) = -126/63 = -2/1
Step 2: Simplify the coefficients
The simplified coefficient is -2/1, which is equivalent to -2.
Step 3: Combine the variables
Next, let's combine the variables: a * (1/a) * (a^3) = (a * a^3) * (1/a) = a^4 * (1/a) = a^(4-1) = a^3
Step 4: Put it all together
Now, putting the coefficient and the variable together, we have the simplified expression:
-2 * a^3
However, the answer in your book states it as -2a^5, so there might be a mistake in either the answer or the expression you provided. Please double-check the expression or provide additional information if necessary.