algebra

Solve by factoring:
10t^2 – t − 2 = 0

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asked by gina
  1. 10t^2 - t - 2 = 0.
    Use the AC Method:
    A*C = 10*(-2) = -20 = -5*4.
    Select the pair of factors whose sum = -1:
    10t^2 - 5t+4t - 2 = 0,
    Form 2 factorable pairs by grouping:
    (10t^2-5t) + (4t-2) = 0,
    Factor each binomial:
    5t(27-1) + 2(2x-1) = 0,
    (2t-1)(5t+2) = 0,

    2t-1 = 0,
    2t = 1,
    t = 1/2.

    5t+2 = 0,
    5t = -2,
    t = -2/5.

    Solution Set: t = 1/2, and-2/5.

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    posted by Henry
  2. Correction:
    5t(27-1) should be 5t(2t-1).

    All variables should be t and NOT x.

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    posted by Henry

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