algebra

Solve by factoring:
10t^2 – t − 2 = 0

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1. 10t^2 - t - 2 = 0.
Use the AC Method:
A*C = 10*(-2) = -20 = -5*4.
Select the pair of factors whose sum = -1:
10t^2 - 5t+4t - 2 = 0,
Form 2 factorable pairs by grouping:
(10t^2-5t) + (4t-2) = 0,
Factor each binomial:
5t(27-1) + 2(2x-1) = 0,
(2t-1)(5t+2) = 0,

2t-1 = 0,
2t = 1,
t = 1/2.

5t+2 = 0,
5t = -2,
t = -2/5.

Solution Set: t = 1/2, and-2/5.

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posted by Henry
2. Correction:
5t(27-1) should be 5t(2t-1).

All variables should be t and NOT x.

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posted by Henry

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