Ammonia gas is passed into water ,yielding a solution of density 0.93 g/cm^3 and containing 18.6% NH3 by wieght .The mass of NH3 per cc of the solution is?
For the reaction Ba(OH)2+2HCLO3 -> Ba(CIO3)2+2H2O calculate the no. of mole of H2O formed .when .01 mole of Ba(OH)2 is treated with 0.0250 moles of HCLO3
1 cc x 0.93 g/cc x 0.186 = ?gNH3/cc.
See your post above for the second part.
To find the mass of NH3 per cc (cubic centimeter) of the solution, we can follow these steps:
Step 1: Determine the density of the solution.
Given: Density of the solution = 0.93 g/cm^3
Step 2: Calculate the mass of the solution per cc (g/cm^3).
Since density = mass/volume, rearrange the equation to solve for mass:
Mass = Density × Volume
Step 3: Determine the volume of the solution per cc.
Given: Volume = 1 cc (since we are calculating per cc of the solution)
Step 4: Calculate the mass of the solution per cc:
Mass = Density × Volume
Mass = 0.93 g/cm^3 × 1 cc
Mass = 0.93 g/cc (grams per cubic centimeter)
Step 5: Determine the mass of NH3 in the solution.
Given: NH3 concentration by weight = 18.6%
Step 6: Calculate the mass of NH3 per cc:
Mass of NH3 = (18.6/100) × Mass of solution
Mass of NH3 = (18.6/100) × 0.93 g/cc
Mass of NH3 = 0.173 g/cc (grams per cubic centimeter)
Therefore, the mass of NH3 per cc of the solution is 0.173 g/cc.