At what angle is an object launched if its initial vertical speed is 3.75 m/s and its initial horizontal speed is 4.50 m/s?
tanA = y/x =375/450 = 0.8333,
A = 39.8 deg.
To find the launch angle of an object, given its initial vertical and horizontal speeds, we can use trigonometry. The launch angle can be determined using the following formula:
θ = arctan(Vy / Vx),
where θ is the launch angle, Vy is the initial vertical speed, and Vx is the initial horizontal speed.
In this case, the initial vertical speed (Vy) is given as 3.75 m/s, and the initial horizontal speed (Vx) is given as 4.50 m/s. Substituting these values into the formula, we can calculate the launch angle as follows:
θ = arctan(3.75 / 4.50).
Using a scientific calculator or an online calculator with trigonometric functions, you can find that the arctan of 3.75 divided by 4.50 is approximately 38.66 degrees.
Therefore, the object is launched at an angle of approximately 38.66 degrees.