Physics- impuse and force

A car is moving to the right with a speed of 20 m/s. A large SUV is moving to
the left at a speed of 20 m/s. The SUV has a mass three times that of the small car. They have
an totally inelastic head-on collision in an intersection. There are two passengers in each
vehicle, one seat-belted and the other not seat-belted. All the passengers weigh the same. The
non-seat-belted passengers both collide with the dashboard of their respective cars.

Rank the magnitude of the IMPULSE experienced by the four passengers in this collision
from smallest to largest. If two impulses are equal, then show an equals sign between
them.
a. SUV belted = SUV non belted < Car Belted = Car non belted
b. Car belted = Car Non belted < SUV belted = SUV non belted
c. SUV belted < SUV non belted < Car belted < Car Non Belted
d. SUV belted < Car belted < SUV non belted < Car non belted

I'm very confused but am guessing that the answer is a.

Rank the magnitude of the FORCES experienced by the four passengers in this collision,
from smallest to largest. If two forces are equal, then show an equals sign between them.

b. Car belted = Car Non belted < SUV belted = SUV non belted
c. SUV belted < SUV non belted < Car belted < Car Non Belted
d. SUV belted < Car belted < SUV non belted < Car non belted

I believe d is the correct answer

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asked by Casey
  1. yes D is a correct option Becouse the belted man experience less impulse than non belted but why this sooooo because when collision occur than the belted body experince less impulse than non belted body because of bult. the bult Exceed the time duration ad lose the motion

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