A car is moving to the right with a speed of 20 m/s. A large SUV is moving to
the left at a speed of 20 m/s. The SUV has a mass three times that of the small car. They have
an totally inelastic head-on collision in an intersection. There are two passengers in each
vehicle, one seat-belted and the other not seat-belted. All the passengers weigh the same. The
non-seat-belted passengers both collide with the dashboard of their respective cars.
Rank the magnitude of the IMPULSE experienced by the four passengers in this collision
from smallest to largest. If two impulses are equal, then show an equals sign between
them.
a. SUV belted = SUV non belted < Car Belted = Car non belted
b. Car belted = Car Non belted < SUV belted = SUV non belted
c. SUV belted < SUV non belted < Car belted < Car Non Belted
d. SUV belted < Car belted < SUV non belted < Car non belted
I'm very confused but am guessing that the answer is a.
Rank the magnitude of the FORCES experienced by the four passengers in this collision,
from smallest to largest. If two forces are equal, then show an equals sign between them.
b. Car belted = Car Non belted < SUV belted = SUV non belted
c. SUV belted < SUV non belted < Car belted < Car Non Belted
d. SUV belted < Car belted < SUV non belted < Car non belted
I believe d is the correct answer
yes D is a correct option Becouse the belted man experience less impulse than non belted but why this sooooo because when collision occur than the belted body experince less impulse than non belted body because of bult. the bult Exceed the time duration ad lose the motion
To determine the magnitudes of the impulses and forces experienced by the passengers in the collision, we need to understand the principles of momentum and Newton's laws of motion.
Impulse is the change in momentum of an object and is calculated by multiplying the force exerted on an object with the time interval over which the force is applied. In this case, since the collision is totally inelastic, the two vehicles stick together after the collision.
Now let's analyze the situation based on the given information:
1. Car: The car is moving to the right with a speed of 20 m/s. Since the collision is inelastic, the car will come to a stop after colliding with the SUV. The mass of the car is three times smaller than that of the SUV.
2. SUV: The SUV is moving to the left with a speed of 20 m/s. It also comes to a stop after the collision.
Since the car and the SUV have equal and opposite velocities, they cancel each other out, resulting in a final velocity of zero for both vehicles. The collision causes a transfer of momentum from the car to the SUV.
Now let's consider the ranking of the impulses experienced by the four passengers:
a. SUV belted = SUV non-belted < Car belted = Car non-belted
- The impulse experienced by the belted passengers in both vehicles will be equal since they are restrained by the seatbelts and have the same mass.
- The impulse experienced by the non-belted passengers in both vehicles will be equal since they are not restrained and collide with the dashboard. Since the mass of the car is three times smaller, the deceleration experienced by the non-belted passengers in the car will be three times greater than that experienced by the non-belted passengers in the SUV.
Therefore, option a is correct.
Now let's consider the ranking of the forces experienced by the passengers:
d. SUV belted < Car belted < SUV non-belted < Car non-belted
- The force experienced by the belted passengers in the SUV is less than that experienced by the belted passengers in the car, as the SUV has a greater mass.
- The force experienced by the non-belted passengers in the SUV is less than that experienced by the non-belted passengers in the car, as the mass of the car is three times smaller, resulting in a greater deceleration and, therefore, a greater force.
Therefore, option d is correct.