60 ml of solution A is mixed with 120 ml of solution B to produce solution C which contains 8% of pure acid. If 80ml of solution A is mixed with 40ml of solution B, a solution D containing 10% of pure acid can be produced. find the percentage of pure acid in solution A?
To solve this problem, we need to set up a system of equations based on the given information. Let's assume that the percentage of pure acid in solution A is "x".
From the first scenario, where 60 ml of solution A is mixed with 120 ml of solution B to produce a solution C containing 8% pure acid, we can set up the following equation:
(60 ml * x%) + (120 ml * 0%) = (60 ml + 120 ml) * 8%
This equation represents the total amount of acid in solution A and solution B before and after the mixing. Since solution B has 0% pure acid, it doesn't contribute to the acid content in the final solution.
Simplifying the equation:
(60 ml * x%) = (180 ml) * 8%
Next, let's simplify the equation further:
0.6x = 14.4
Dividing both sides of the equation by 0.6:
x = 14.4 / 0.6
x ≈ 24
Therefore, the percentage of pure acid in solution A is approximately 24%.
Note: In the second scenario, where 80 ml of solution A is mixed with 40 ml of solution B to produce a solution D containing 10% pure acid, we didn't need to consider it in finding the percentage of pure acid in solution A.