An elevator starts from rest with a constant upward acceleration and moves 1m in the first 1.4 s. A passenger in the elevator is holding a 6.3 kg bundle at the end of a vertical chord. what is the tension in the chord as the elevator accelerates? The acceleration of gravity is 9.8 m/s^2. Answer in units of N

Question

An elevator starts from rest with a constant upward acceleration and moves 1m in the first 1.4 s. A passenger in the elevator is holding a 6.3 kg bundle at the end of a vertical chord. what is the tension in the chord as the elevator accelerates? The acceleration of gravity is 9.8 m/s^2. Answer in units of N

Im not sure if i solved this right, but here is my work:

6.3(9.8)=61.74 N

Answer 1

No, you left out the vertical acceleration

a up = 1/1.4 = .714 m/s^2

F = m a
F up - mg = m a
Fup = m (g+a)
Fup = 6.3 (9.8+.714)
Fup = 66.24 N

Answer 2

To find the tension in the chord as the elevator accelerates, you need to consider the forces acting on the bundle.

Let's break down the problem:

1. The bundle experiences two forces: its weight (mg) acting downward and the tension in the chord acting upward.
2. The weight of the bundle is given by the formula: weight = mass * acceleration due to gravity.
In this case, the weight of the bundle is: weight = 6.3 kg * 9.8 m/s^2 = 61.74 N.
So, your calculation of the weight of the bundle is correct.

Now, to find the tension in the chord, you need to consider the net force acting on the bundle. Since the elevator is accelerating upward, there is an additional force acting on the bundle in the upward direction.

The net force acting on an object is given by the formula: net force = mass * acceleration.

In this case, the mass of the bundle is given as 6.3 kg, and the acceleration is unknown. However, we can find the acceleration using the given distance traveled and time.

The formula for distance traveled during constant acceleration is: distance = (1/2) * acceleration * time^2.

Using the given values, we have: 1 m = (1/2) * acceleration * (1.4 s)^2.
Simplifying the equation, we get: acceleration = (2 * 1 m) / (1.4 s)^2 = 2.0408 m/s^2 (approx).

Now, we can calculate the net force acting on the bundle:
net force = mass * acceleration = 6.3 kg * 2.0408 m/s^2 = 12.82104 N (approx).

Since the net force is the sum of the tension and weight, we can write:
net force = tension - weight.

Rearranging the equation and substituting the values,
tension = net force + weight = 12.82104 N + 61.74 N = 74.56104 N (approx).

So, the tension in the chord as the elevator accelerates is approximately 74.56104 N.