a woman walks 250 m in the direction 30 degree east of north,then 175 m directly east.A) using graphical methods,find her final displacement from the starting point.B) compare the magnitude of her displacement with the distance she walked.,
a woman walks 250 meter in the direction of 35 east of north, then 170 meter directly east.(A) using graphical methods , find her displacement from the starting point.(B) compare the magnitude of her displacement with she walked.
No any response because I am a student
To solve this problem using graphical methods, we can represent the woman's movements as vectors on a coordinate plane.
Step 1: Draw the starting point (A) as the origin (0,0).
Step 2: Draw a vector (AB) representing the woman's first movement of 250 m in the direction 30 degrees east of north. To do this, draw an arrow at point A that goes 30 degrees clockwise from the north direction and has a length of 250 m.
Step 3: Draw a vector (BC) representing the woman's second movement of 175 m directly east. Extend the arrow from point B, parallel to the x-axis, with a length of 175 m.
Step 4: Find the vector sum by connecting the starting point (A) to the endpoint (C) using a straight line segment. This line segment represents the woman's final displacement.
Step 5: Measure the magnitude of the final displacement vector (AC) using a ruler. This represents the woman's displacement from the starting point.
To compare the magnitude of her displacement with the distance she walked:
Step 6: Measure the total distance covered by adding the lengths of the two vectors (AB and BC). This represents the total distance she walked.
Step 7: Compare the magnitude of her displacement (AC) with the total distance she walked.
north displacement = 250 cos 30 = 216.5
east displacement = 250 sin 30 + 175 = 300
displacement = sqrt (north^2+east^2)
= 370 m
total distance = 250+175 = 425