Algebra II
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13.8.33 Question Help If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h=−16t squared + vt +s, where h is in
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In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of
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object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of time in seconds after the ball was thrown. Also,
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The formula h=vt−16t^2 gives the height h, in feet, of an object projected into the air with an initial vertical velocity v, in feet per second, after t seconds. If an object is projected upward with an initial velocity of 112
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