What is the axis of symmetry of f(x)= -1/2^2-x+4?
Use parentheses
f(x)= (-1/2)^2-x+4
f(x) = 1/4 - x + 4
f(x) = 4.25 - x
or
y = -1 x + 4.25
that is a straight line of slope -1.
I suppose you could say it is symmetric about any line of slope +1, but I suspect you have a typo.
To find the axis of symmetry of a quadratic function in the form f(x) = ax^2 + bx + c, you can use the formula x = -b / (2a).
In this case, the quadratic function is f(x) = -1/2^(2-x) + 4. Comparing it to the general form, we can see that a = -1/2^2, b = 1, and c = 4.
Now, let's plug these values into the formula x = -b / (2a):
x = -(1) / [2 * (-1/2^2)]
x = -1 / (-1/2)
x = -1 * (2/1)
x = -2
Therefore, the axis of symmetry for the given quadratic function is x = -2.